Question

A body starts from rest reaches velocity of 8ms‐¹ in 4 seconds find the acceleration

Answer 1

U=0

v=8m/s

time=4 sec

A=?

We will use first equatiom of motion

V=u+at

8=0+4×a

8=4a

a=2m/s^2

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=2\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Final \: velocity(v) = 8 \: m/s \\ \\ \tt: \implies Time(t) = 4 \: sec \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Acceleration(a) =?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 8 = 0 + a \times 4 \\ \\ \tt: \implies 8 = a \times 4 \\ \\ \tt: \implies a= \frac{8}{4} \\ \\ \green{\tt: \implies a = {2 \: m/s}^{2} } \\ \\ \blue{\bold{Some \: related \: formula}} \\ \\ \orange{ \tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{ \tt \circ \: s = ut + \frac{1}{2} {at}^{2} }$