a body starts from rest. what is the ratio of the distance travelled by the body during 3rd and 4th second
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Answered by
425
Hi friend,
The formula is
Sn= u+a/2(2n-1)
For t=n=3
S3= 0+10/2(5)
S3= 50/2 m
Similarly,
S4= 0+10/2(7)
S4= 70/2m
S3/S4= 50/2×2/50
S3:S4= 5:7
Hope this helped you a little!!!!
The formula is
Sn= u+a/2(2n-1)
For t=n=3
S3= 0+10/2(5)
S3= 50/2 m
Similarly,
S4= 0+10/2(7)
S4= 70/2m
S3/S4= 50/2×2/50
S3:S4= 5:7
Hope this helped you a little!!!!
Answered by
65
hope this will help you market is as brainliest if you are satisfied by my response thanks
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