Question

A body starts from rest. What is the ratio of the distance travelled by the body during 4th and 3rd sec

Answer 1

Answer of this is 7:5

Answer 2

Hello friend...!!

We should calculate the ratio of the distance travelled by the body in 4th and 3rd second.

• according to equations of motion,

Sn = u + a/2(2n-1)

At 4 sec,

S4 = 0 + a/2( 8-1)

S4 = 7a/2 --------------( 1 )

Similarly,

S3 = 0 + a/2 ( 6 - 1 )

S3 = 5a/ 2 --------------( 2 )

Now the ratio between, S4 and S3 is,

S4 / S3 = 7a/ 2 X 2 / 5a

Therefore,

S4 / S3 = 7/ 5

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Hope it helps...!!