The mean of 5 numbers is 30,if one number is excluded there mean becomes 28 find the excluded number ?
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Answered by
284
Let the numbers be a,b,c,d,e.
Therefore, (a+b+c+d+e)/5=30
a+b+c+d+e=150
Let the excluded number is e
Then, (a+b+c+d)/4=28
a+b+c+d=112
Therefore,(a+b+c+d+e)-(a+b+c+d)=150-112
e=38
Therefore, (a+b+c+d+e)/5=30
a+b+c+d+e=150
Let the excluded number is e
Then, (a+b+c+d)/4=28
a+b+c+d=112
Therefore,(a+b+c+d+e)-(a+b+c+d)=150-112
e=38
Answered by
131
Let the numbers be a,b,c,d,e.
Therefore, (a+b+c+d+e)/5=30
a+b+c+d+e=150
Let the excluded number is e
Then, (a+b+c+d)/4=28
a+b+c+d=112
Therefore,(a+b+c+d+e)-(a+b+c+d)=150-112
e=38
Therefore, (a+b+c+d+e)/5=30
a+b+c+d+e=150
Let the excluded number is e
Then, (a+b+c+d)/4=28
a+b+c+d=112
Therefore,(a+b+c+d+e)-(a+b+c+d)=150-112
e=38
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