Physics, asked by messi2395, 11 months ago

A body starts from rest with a uniform acceleration of 1m/s^2.The average velocity in the time interval of t=3s and t=5s is:(a)4m/s (b)1m/s (c)0.4m/s (d)4m/s.

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Answers

Answered by kaalipavan
1

Answer:

Explanation:

u = 0m/s

a = 1m/s^2

t = 3s

v= v-u=at

=>v=at+u

=>v=3

Similarly 5s = 5m/s^2

3+5 / 2 = 4

so average velocity in the interval = 4m/s

Answered by kumar3610
1

Explanation:

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