Question

A body starts from rest with a uniform acceleration of 2m/s^. Find the distance covered by the body in 2s

Answer 1

Answer:

Answer = 4 m

Explanation:

Initial velocity, u = 0

Acceleration, a = 2 m/sec²

Time , t = 2sec

v = u + at

v = 0 + 2 ×2

v = 4 m/ sec

v²-u²=2as

4²-0²=2×2×s

16-0=4s

16=4s

16/4= s

4= s

Therefore distance covered by the body = 4 m

Answer 2

Answer:

4 Meters

Explanation:

U = 0

S = DISTANCE

A = 2 (ACCELERATION)

T = 2s

SO,

USING THE EQUATION. S = UT + 1/2*AT²

THEREFORE

S = 0 * 2 + 1/2 * 2 * 2²

S = 0 + 4

S = 4