a body starts from rest with uniform acceleration. if it covers s1 distance in first 4 second and s2 distance in next 4 seconds then prove that s2 = 3s1
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haya23:
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Answered by
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we know that
u=0
a=a
t1=4
t2=8
so,
s1=ut1+1/2×a×t1^2
=0+1/2×a×4^2
=8a ....................1
s2=ut2+1/2×a×t2^2
=0+1/2×a×8^2
=32a
distance travelled in next 4 second -
s2-s1= 32a-8a=24a .........2
So from equation 1st and 2nd we get-
s2=3s1
u=0
a=a
t1=4
t2=8
so,
s1=ut1+1/2×a×t1^2
=0+1/2×a×4^2
=8a ....................1
s2=ut2+1/2×a×t2^2
=0+1/2×a×8^2
=32a
distance travelled in next 4 second -
s2-s1= 32a-8a=24a .........2
So from equation 1st and 2nd we get-
s2=3s1
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