Question

A body starts moving from a state of rest with an acceleration of 0.5 m/s .after covering a distance of 250 m the velocity of the body will be

Answer 1

Answer:

2as=v²-u²

a==0.5m/s²

u=0m/s

s=250m

v²=2as+u²

v²=2×0.5×250+0²

v²=250m

v²=250

v=15.811m/s

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Answer 2

The final velocity of the body will be 5√10 ms⁻¹

Explanation:

• Acceleration of any body is defined as the rate of change of velocity of the body. A body is said to be accelerated if its velocity increases with time, if velocity is constant then acceleration of the body is zero and if velocity decreases with time body retards that is producing negative acceleration

Given, body initially at rest that is initial velocity is zero

u = 0 ms⁻¹

acceleration of the body = 0.5 ms⁻²

distance covered = 250 m

we can calculate the final velocity by using equation of motion

=> v² - u² = 2 as

where, v = final velocity

u = initial velocity

a = acceleration of the body

s = displacement or distance covered by the body

=> v² - 0² = 2 (0.5) 250

=> v² = 250

=> v = √250

=> v = 5√10 ms⁻¹

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