Find the smallest value of A if 10A + 5 is divisible by 3
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the smallest a value is 1
: 10*1 + 5
: 10 + 5
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Confirming by induction method. therefore, 10a + 5 = 0 which is divisible by 3. therefore (1/10)*10 + 5 => 6 which is divisible by 3. likewise the smallest value of a that divides 10a + 5 by 3 is -(3n+2)/10 where n is -ve infinity.
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