a body starts moving from rest with an acceleration of 20cm/s^2 . what is the distance covered in the 10th second ?
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Answered by
5
Answer:
Explanation:
As the body is starting from rest ,
Initial Velocity = u = 0 m/s
Acceleration = a = 20 cm/s²
Time = t = 8 sec
Distance traveled = s
Equation of Motion :
s = ut + 1/2at²
= 0 + 1/2 × 20 × 8 × 8
= 640 cm [ 1 m = 100 cm ]
= 640 /100 m
= 6.4 meters
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2
Answer:
I don't know answer sorry
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