Question

a body starts rolling over a horizontal surface with an initial velocity of 0.5 m/s due to the friction its velocity decreases at the rate of 0.05 m/s2 how much time will it take for the body to stop (9th standard method)

Answer 1

Here the formula to be taken is v is equal to u plus a multiplied to t

We have to find t or time

So, 0 = 0.5 plus (-0.05) multiplied by t

Then t is equal to – 0.5 divided by -0.05

Straightly, the answer is 10 that means time taken for the body to stop is 10 seconds

Answer 2

u=0.5 m/s

a=-0.05 m/s²

v=0

By first equation of motion, we have:

v=u+at

0=0.5-0.05t

0-0.5=-0.05t

-0.5=-0.05t

0.5/0.05=t

50/5=t

10 s=t