A body starts to slide over a horizontal surface with an initial velocity 0.5m/s. Due to the friction it's velocity decreases at the rate of 0.05m/s sq. How much time will it take to stop
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v = 0.05
u = 0.5
a = 0
t = ?
v=u+at
0.05 = 0.5 + 0(t)
0.5 - 0.05 = t
t = 0.45
u = 0.5
a = 0
t = ?
v=u+at
0.05 = 0.5 + 0(t)
0.5 - 0.05 = t
t = 0.45
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