a body starts to slide over a horizontal surface with an initial velocity of 0.5 metre per second due to friction its velocity decreases at the rate of 0.05 metre per second square how much time will it take the body to stop and also find the stopping distance
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U=0.5 m/s
a=-0.05 m/s²
v=0
By first equation of motion, we have:
v=u+at
0=0.5-0.05t
0-0.5=-0.05t
-0.5=-0.05t
0.5/0.05=t
50/5=t
10 s=t
Answered by
2
Answer:
U=0.5 m/s
a=-0.05 m/s²
v=0
By first equation of motion, we have:
v=u+at
0=0.5-0.05t
0-0.5=-0.05t
-0.5=-0.05t
0.5/0.05=t
50/5=t
10 s=t
Explanation:
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