Question

A body starts with an initial velocity of 10 m s' and
acceleration 5 m s. Find the distance covered by
it in 5 s.
Ans. 112.5 m

​

Answer 1

112.5m

Explanation:

S=UT+1/2AT(T)

S=10(5)+1/2(5)×25

S=50+125/2

S=(100+125)/2

S=225/2

S=112.5

hope it is helpful to you

please mark it as brainliest answer

Answer 2

u = 10m/s , acc = 5m/s^2 , t = 5sec , v = ? , s = ?

From 1st equation of motion ,

v = u + at

=> v = 10 + 5(5) = 10 + 25 = 35m/s

From 2nd equation of motion ,

V^2 - u^2 = 2as

(35)^2 - (10)^2 = 2(5)(s)

1225 - 100 = 10(s)

=> 1125/10 = s => s = 112.5m