Question

A body starts with an initial velocity of 10 m s and acceleration 5 ms. Find the distance covered
by it in 5 s.
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Answer 1

Answer:

Explanation:

Hi there!!

Here's your answer

Given,

Initial velocity (u) = 10m/s

Acceleration (a) = 5m/s²

Time (t) = 5sec

Distance (s) = ?

Using the 2nd equation of uniform motion,

s = ut + 1/2at²

s = 10(5) + 1/2 × 5 × (5)²

s = 50 + 62.5

s = 112.5

This,

The distance is 112.5 m .

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Answer 2

Answer:

using 2 equation of motion

S=ut+1/2at2

s=10*5+1/2*5*25

s=50+62.5

s=112.5.