a body starts with an initial velocity of 10 m/s and acceleration 5 m s-2 .find the distance covered by it in 5s.
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Answered by
87
Hi there!!
Here's your answer
Given,
Initial velocity (u) = 10m/s
Acceleration (a) = 5m/s²
Time (t) = 5sec
Distance (s) = ?
Using the 2nd equation of uniform motion,
s = ut + 1/2at²
s = 10(5) + 1/2 × 5 × (5)²
s = 50 + 62.5
s = 112.5
This,
The distance is 112.5 m .
=========================
Hope you're helped :D
Here's your answer
Given,
Initial velocity (u) = 10m/s
Acceleration (a) = 5m/s²
Time (t) = 5sec
Distance (s) = ?
Using the 2nd equation of uniform motion,
s = ut + 1/2at²
s = 10(5) + 1/2 × 5 × (5)²
s = 50 + 62.5
s = 112.5
This,
The distance is 112.5 m .
=========================
Hope you're helped :D
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