Question

A body starts with an initial velocity of 10 meter per second and acceleration 5 meter per second square. Find the distance covered by it in 5 sec .​

Answer 1

Answer:

25 m

by motion 1 law of motion

Answer 2

Given,

Initial Velocity, u = 10 m s^(-1)

Acceleration, a = 5 m s^(-2)

Time taken for covering the distance, t = 5 s

Well, we know the second kinematic equation.

s = u t + (a t²) / 2

Remember, this formula is possible only for constant acceleration. Here it's possible. So,

s = 10 × 5 + (5 × 5²) / 2

s = 50 + 125 / 2

s = 50 + 62.5

s = 112.5 m

Hence the displacement is 112.5 metres.

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