Question

A body starts with an initial velocity of 15 m/s and acceleration 2 m s-2 .find the distance covered by it in 5s.

Answer 1

Answer:

100 m

Explanation:

as the acceleration is constant at doesnt change its sign

∴ s = ut + 1/2at²

 s= 15×5 + 0.5×2×5²

s = 75+25

s = 100 m

Answer 2

Answer:

s = ut + 1/2at^2

s = 15 *5 + 1/2 *2 * 25

s = 75 + 25

s = 100 m

I hope it helps .