Question

a body starts with an initial velocity of 20ms and acceleration 5m/S2. find the distance covered by it in 5s​

Answer 1

Explanation:

This is the answer

Hope u like it

Answer 2

Answer:

$\boxed{\mathfrak{Distance \ covered \ (s) = 162.5 \ m}}$

Given:

Initial velocity (u) = 20 m/s

Acceleration (a) = 5 m/s²

Time taken (t) = 5s

To Find:

Distance covered (s) by the body in 5s

Explanation:

$\sf From \: 2^{nd} \: equation \: of \: motion:$

$\boxed{ \bold{ \sf s = ut + \frac{1}{2} a {t}^{2} }}$

Substituting values of u, a & t in the equation:

$\sf \implies s = 20 \times 5 + \frac{1}{2} \times 5 \times {5}^{2} \\ \\ \sf \implies s = 100 + \frac{1}{2} \times 5 \times 25 \\ \\ \sf \implies s = 100 + \frac{1}{2} \times 125 \\ \\ \sf \implies s = 100 + 62.5 \\ \\ \sf \implies s = 162.5 \: m$

$\therefore$

Distance covered (s) by the body in 5s = 162.5 m