a body starts with some initial velocity along a straight line.after 3s it is found to be at a distance of 15m from the start.after 4s it is seen at the starting point.what is the initail vel if acceleration is const?
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The particle has distance 15m in 3sec.
: . initial velocity u=d/t = 15/3= 5m/s since, accln. is constant(i.e. a=0) initial and final velocity will be equal.
u =5(initial velocity),
v=5(final velocity),
t1=3s
t2=4s
a= (v-u)/(t2-t1)
a=(5-5)/(4-3)
a=0.
: . initial velocity = final velocity =5m/s.
: . initial velocity u=d/t = 15/3= 5m/s since, accln. is constant(i.e. a=0) initial and final velocity will be equal.
u =5(initial velocity),
v=5(final velocity),
t1=3s
t2=4s
a= (v-u)/(t2-t1)
a=(5-5)/(4-3)
a=0.
: . initial velocity = final velocity =5m/s.
AbhishGS:
accln. means rate of increase in velocity.
and velocity is not increasing means accln is zero.
a ball thrown upwards is also acted upon a constant acceleration. 10m/sec square...can i say that its acceleration is zero
u got ur ans.
just think. Let it not be zero but still accln is constant so initial and final velocity will be same
if it is 10 then also u get velocity 5 m/s
hqqn right
haan right
okk
good luck : )
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