a body strikes the floor with a velocity u and rebounds at the same speed the change in velocity would be
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Let x be the change in velocity. Then,
V+x = -V
=> x = -2V
Thus, we can see that the change in velocity is twice the the negative of the initial velocity. Cheers. :)
V+x = -V
=> x = -2V
Thus, we can see that the change in velocity is twice the the negative of the initial velocity. Cheers. :)
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