Question

A body, thrown upwards with some velocity, reaches the maximum height of 20 m . Another body with double the mass thrown up, with double initial velocity will reach a maximum height of

Answer 1

Answer:

Irrespective of mass Hmax=u2/2g=50m 

if we double the initial velocity u then Hmax will get 4 times means 200m .

Answer 2

Answer:

A body is at a maximum height of 20m another body with double the mass is thrown up with the initial velocity twice that of the first body the maximum height reached by it is  $200m$

Explanation:

• We have an equation of motion connecting initial velocity (u), final velocity (v), displacement (s), and acceleration(a) of a moving body as

         $V^{2} =u^{2} +2as$

• there is no terms regarding the mass of the body

• The final of a body at maximum height is zero

From the question, we have

maximum height reaches by the first body $s_{1}=20m$

⇒

$0=u^{2}+2a*20\\\frac{u^{2} }{2a} =20$

the initial velocity of the second body $=2u$

⇒$0=(2u)^{2} +2as_{2} \\\\s_{2} =4(u^{2}/2a )=4*s_{1}=80m$

therefore the maximum height of the second body is $200m$