A body thrown vertically up with a velocity reaches a maximum height of hundred metre define other body of the mass of the former is thrown up with a velocity twice the former of maximum height reached?
Answers
Answered by
1
Answer:
solved
Explanation:
1st. boby
max height H = u²sin²∝/2g = u²/2g = u²/20 = 100, u = 20√5 m/s
2nd. boby
max height H = u'²sin²∝/2g = u'²/2g = 4u²/2g = 400m.
Similar questions