Question

a body thrown vertically up with initial velocity 52 m/s second from the ground passes twice point at h height above at an interval of 10 seconds .The height H is
(1)22 m
(2)10.2 m
(3)11.2 m
(4)15 m​

Answer 1

initial velocity,u = 52 m/s

s=ut+1/2gt²s = 520+1/2(-10)(10)²s = 520-5(10)²s = 520-500=20m

so the height of H is 20m

Answer 2

Answer:

Explanation:

initial velocity,u = 52 m/s

s=ut+1/2gt²s = 520+1/2(-10)(10)²s = 520-5(10)²s = 520-500=20m

so the height of H is 20m