A flask containing air is heated from 300 kelvin to 500 kelvin
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Assume the flask to have a volume of 1L
Since the pressure is kept constant,
we have, V1/T1 =V2/T2
V1 = 1L and T1 = 300K, T2 = 500K
Therefore V2 = 500/300 = 1.66 L i.e. the gas has expanded.
Since the volume of the flask can contain only 1L of air the remaining 0.66 L will escape i.e 39.75 %
Since the pressure is kept constant,
we have, V1/T1 =V2/T2
V1 = 1L and T1 = 300K, T2 = 500K
Therefore V2 = 500/300 = 1.66 L i.e. the gas has expanded.
Since the volume of the flask can contain only 1L of air the remaining 0.66 L will escape i.e 39.75 %
Answered by
7
Assume the flask to have a volume of 1L
Since the pressure is kept constant,
we have, V1/T1 =V2/T2
V1 = 1L and T1 = 300K, T2 = 500K
Therefore V2 = 500/300 = 1.66 L i.e. the gas has expanded.
Since the volume of the flask can contain only 1L of air the remaining 0.66 L will escape i.e 39.75 %
Hope it helps you.
Since the pressure is kept constant,
we have, V1/T1 =V2/T2
V1 = 1L and T1 = 300K, T2 = 500K
Therefore V2 = 500/300 = 1.66 L i.e. the gas has expanded.
Since the volume of the flask can contain only 1L of air the remaining 0.66 L will escape i.e 39.75 %
Hope it helps you.
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