Question

A body thrown vertically upward remains in air for 2 seconds another body is thrown vertically upward with double the velocity how long does it stay in air

Answer 1

Explanation:

a = 9.8 m/s²

v = o

case 1

u = u m/s

t = 2 s

v = u + at

u = 19.6 m/s

case 2

u = 2u

= 39.2 m/ s

v = u + at

t =39.2/9.8

t = 4s