Physics, asked by namanjeet9583, 1 year ago

A body thrown vertically upward with a velocity of 20 metre per second from the top of the tower 60 metre high when the body reach the ground

Answers

Answered by Question1Answer2
1

Answer:

Sorry, here's the explanation

Explanation:

u = 20

time of flight until it reaches initial position = 2u/g = 4 s

Then, for it to return to the ground -

s = 60

a = 10

u = 20

s = ut+1/2 at^2

60 = 20t + 5t^2

By factorising it, we get t = 2

Total time = 4 + 2 = 6 s.

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