A body thrown vertically upward with a velocity of 20 metre per second from the top of the tower 60 metre high when the body reach the ground
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Answer:
Sorry, here's the explanation
Explanation:
u = 20
time of flight until it reaches initial position = 2u/g = 4 s
Then, for it to return to the ground -
s = 60
a = 10
u = 20
s = ut+1/2 at^2
60 = 20t + 5t^2
By factorising it, we get t = 2
Total time = 4 + 2 = 6 s.
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