Question

a body thrown vertically upwards reaches a maximum height h. it then return to ground . calculate the distance travelled and displacement.​

Answer 1

Answer:

We can solve this problem by using third equation of motion

=> v²= u² + 2as (signs have their usual meaning)

Here s=h

v = 0 ( at the topmost point velocity becomes 0 for an instant).

And a = g ( acceleration due to gravity)

=> 0²= u² + 2(-g)h (taking upward direction as positive)

0 = u² - 2gh

2gh = u²

Therefore, h = u²/2g

This is half the distance travelled as the ball returns on the ground

So the distance travelled is u²/g

Since the ball returns to the ground

Therefore it's displacement is 0

Explanation:

The answer itself is well explained thus I hope you don't need further explanation

Answer 2

Answer:

Distance is 2h

displacement is 0

Explanation: