Math, asked by lalruatsangihhp7drvx, 1 year ago

A body thrown verticaly upwarda risea up toa height of 10m and comes back to the initiat position the total distance travelled by the body (20m)


Nikki57: What to find?

Answers

Answered by ExoticExplorer
1
The question is not clear at all, but even then, I would like to make a guess at the correct question:

A body thrown vertically upward rises upto a height of 10m and come back to initial position. calculate
(a) the total distance travelled by a body
(b) displacement of the body

Anyways, here's your answer:

Let's consider the initial position of body as A and final position of body as B.

 

If, the body goes from A to B and comes back from B to A , it's distance travelled will be →

 

2 × ( Distance between A and B) , as the body travels same path two times

 

So, distance travelled = 2 × 10m = 20m

 

As , the body comes back to it's initial position A , The distance between final and initial position is 0 , So the displacement is also 0.

 

An alternate approach:

(a) The body goes up 10 m and therefore come down by 10 m. So total distance it travels is 10 m + 10 m = 20 m.

 

(b) Displacement is shortest distance between initial and final point. The body comes back to it initial point so its displacement = 0

 

Hope This Helps :)


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