Question

A body tied to one end of a string is made to revolve in a vertical plane. Derive the expression for (i) tension at the bottom and top of the circle. (ii) minimum velocity at the lowest point so that it is just able to loop the vertical loop and (c) the minimum velocity at the top.

Answer 1

T = m/r (u2 -3gh + gr)  

Explanation:

• Let the velocity of the body denoted by 'v' at the vertical circle's point P. Let us assume that the lowest point is denoted as L. At L, the velocity is 'u'.  

By the conservation of energy:  

At point P, the energy is = Energy at point L  

½ mv2 + mgh = ½ mu2  

V2 + 2gh = u2    

At point P, let us consider the centripetal force:    

T - mgcosϴ = mv2/r ------ Equation (1)  

When the values are substituted in equation (1), we obtain:    

T = m/r (u2 -3gh + gr)  

To learn more:    

1. Explain motion in a vertical circle. Obtain expression for velocity and tension in string when body moves in vertical circle: https://brainly.in/question/7431024  

2. A body of 1kg is suspended by string. the tension in thread if the body moves ip with an acceleration of 5 m/s^2 is (g=10m/s^2)?: https://brainly.in/question/11765442

Answer 2

Answer:

I hope this will help you tq