Question

A body travel 2 m in the 2nd second and 6m in the next four second what will
be distance travelled in9th second

Answer 1

Analyzing the value you can see that, motion is not accelerated.

Say d=vt+cd=vt+c then, d2=vt2+c & d4=vt4+cd2=vt2+c & d4=vt4+c

Putting the values we get,

2=v×2+c & 6=v×4+c2=v×2+c & 6=v×4+c

⟹v=6−24−2=2 and c=−2⟹v=6−24−2=2 and c=−2

d9=2×9−2=16d9=2×9−2=16

Cheers

VM