Physics, asked by ramcharan189, 6 months ago

. A body traveling at a uniform retardation of 5ms-2 has its velocity reduced to

half the initial value in traveling a distance of 540m. Calculate the initial

velocity and the time taken to travel the ​

Answers

Answered by shreyash7121
0

Given,

Initial velocity =u

After 2 cmpenetration, velocity v=

2

u

Apply equation of kinematic

v

2

−u

2

=2as

(

2

u

)

2

−u

2

=2a×2

a=

16

−3u

2

When, Final velocity v

1

=

4

u

Apply kinematic equation of motion

v

1

2

−u

2

=2as

1

(

4

u

)

2

−u

2

=2(

16

−3u

2

)s

1

s

1

=2.5 cm

Hence, for final velocity to be one fourth of initial velocity, body penetrate 0.5 cm more in wood.

Answered By=shreyash. ......

.

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