. A body traveling at a uniform retardation of 5ms-2 has its velocity reduced to
half the initial value in traveling a distance of 540m. Calculate the initial
velocity and the time taken to travel the
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Given,
Initial velocity =u
After 2 cmpenetration, velocity v=
2
u
Apply equation of kinematic
v
2
−u
2
=2as
(
2
u
)
2
−u
2
=2a×2
a=
16
−3u
2
When, Final velocity v
1
=
4
u
Apply kinematic equation of motion
v
1
2
−u
2
=2as
1
(
4
u
)
2
−u
2
=2(
16
−3u
2
)s
1
s
1
=2.5 cm
Hence, for final velocity to be one fourth of initial velocity, body penetrate 0.5 cm more in wood.
Answered By=shreyash. ......
.
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