A body travelling with a velocity of 120 ms-1 accelerates uniformly at the rate of 20 ms -2 for a period of 40 s.
Calculate the velocity and the distance travelled in 40 s.
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Answered by
3
Explanation:
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Answered by
3
Answer:
velocity =680 m/s distance =2090 m
Explanation:
u=120m/s
t=40sec
a=20m/s^2
using 1st equation of motion
v=at-u
= 800-120
= 680 m/s
now by using 3rd equation
s=ut+at^2/2
=120×40 + 20×1600/2
=2090 m
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