The resistances 2 ohm3ohm and 5ohm are connected in
series. If a potential difference of 30 volt is applied
between two ends of the combination, calculate the
potential difference between the ends of each
resistance and heat produced in 3ohm resistor.
Answers
Answer:
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Answer:
voltage acrros 2Ω ,3Ω, 5Ω resistors are 6 v ,9v ,15 v
Power across 3Ω resistor is 27 watt.
Explanation:
Given : Three resistors 2Ω , 3Ω , 5Ω connected in series . potential difference applied across the combination 30 volt.
when resistor are applied across parallel combination current through them is same.
so we begin with calculating current in the circuit .
first we calculate net resistance
R = R₁ + R₂ + R₃
R = 2 + 3+ 5
R = 10Ω
Total current in circuit
V=IR
30 = I ×10
I = 3 Ampere
Now to calculate voltage across each resistor
voltage across 2Ω Resistor
V₁ = IR
V₁ = 3 × 2
V₁= 6Ω
voltage across 3 Ω resistor
V₂= I R
V₂ = 3 × 3
V₂ = 9Ω
Volatge across 5 Ω resistor
V₃ = IR
V₃= 3 × 5
V₃= 15Ω
Power across 3 ohm resistor
P= I² × R
P= 3² × 3
P = 27 watt
Hence , voltage acrros 2Ω ,3Ω, 5Ω resistors are 6 v ,9v ,15 v Power across 3Ω resistor is 27 watt