Question

A body travelling with uniform acceleration crosses two
point A and B with velocities 20 ms-1 and 30 ms-1 respectively.
The speed of the body at the mid-point of A and B is nearest
to​

Answer 1

24.5m/s

Explanation:

the formula for this is:-

√[v1^2+v2^2/2]

√[(20)^2+(30)^2/2]

√[400+900/2]

√[650]≈24.5 m/s.