a body travels 100m in the first two seconds and 104m in the next 4 seconds. How far it will move in the next 4 seconds if the acceleration is uniform.
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Answer:
100=2u+2a
u+a=50.......(1)
6u+18a=204...from the first second......(2)
solve (1) &(2):
u=53
a=-3
In total 10 sec distance travelled:
10u+1/2 x a x 10x10=380m , putting all the values:
so distance covered in next four second=380-204=176m
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