Question

A body travels 2 m in the 2nd second and
6 m in the next four seconds. What will be the
distance travelled in the 9th second?
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Answer 1

Step-by-step explanation:

The initial velocity for this stage is u+2a and final velocity at the end of this stage is u+6a. The average velocity =(2a+6a+2u)/2=u+4a. So, distance covered in the given second stage=6=(u+4a)4.