A body travels 200 cm in the first 2 sec. and 220cm in the next 5 sec. calculate the velocity at the end of the seventh second from the start.
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velocity at the end of first 2 sec
s = ut + 0.5 at^2
a = 2.00 / 0.5 / 4
a = 1 m/s^2
v1 = 2 × 1 = 2 m/s
in second phase
2.20 = 2×5 + 0.5 a 5^2
a = 2.20 - 1.00 / 0.5 / 25
a = 2.4/ 25
final velocity = 2 + 5 × 2.4 / 25 = 2.48 m/s
s = ut + 0.5 at^2
a = 2.00 / 0.5 / 4
a = 1 m/s^2
v1 = 2 × 1 = 2 m/s
in second phase
2.20 = 2×5 + 0.5 a 5^2
a = 2.20 - 1.00 / 0.5 / 25
a = 2.4/ 25
final velocity = 2 + 5 × 2.4 / 25 = 2.48 m/s
kumarsuraj59ks:
sorry bro ! your answer is wrong.this question answered is 2.22m/s.
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