Question

a body travels 25 m during 6th second and 45m during 8th second find its initial velocity and acceleration

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Answer 1

Answer:

Distance (S1) = 25 m

Time (t1) = 6s

Distance (S2) = 45 m

Time (t2) = 8s

Initial velocity (u) = S1/t1

= 25/6 m/s

= 4.166 m/s

Final Velocity (v) = S2/t2

= 45/8 m/s

= 5.625 m/s

Time Interval (t) = (8-6) s

= 2 s

Acceleration (a) = v-u/t

= 5.625-4.166/2 m/s²

= 1.459/2 m/s²

= 0.7295 m/s²

I hope this helps.