Question

A body travels 30m in the interval of 2sec and 50m in the next interval of 2sec, then the acceleration of the body is ?
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Answer 1

As we know that acceleration is equal to
$a = \frac{v - u}{t}$
We know the distance/displacement in this case so we can calculate its initial velocity/speed which is equal to
$\frac{distance \: covered \: in \: the \: first \: inerval}{time \: taken \: }$
$= \frac{30}{2} = 15m {s}^{ - 1}$
While the final velocity will be equal to
$\frac{distance \: covered \: in \: the \: last \: interval}{time \: taken}$

$= \frac{50}{2} m {s}^{ - 1} = 25m {s}^{ - 1}$
If we input the value in the equation of acceleration then

$a = \frac{v - u}{t} = \frac{25 - 15}{2} = 10 \div 2 = 5m {s}^{ - 2}$
The time elapsed will be 2 because the body cahnged its velocity in next 2 second if we plot v - t graph we can observe it. And hence the answer being
$5m {s}^{ - 2}$
Hope it helps you and if possible then please mark it as the brainliest answer