Math, asked by pushpasrihari9999, 4 months ago

a body travels a distance of 10km with a constant speed 30km/h and then next 40km at a catch speed of 50 km/h find distance&displacement

Answers

Answered by priyadharshini3725

0

Answer:

D1=10 km.

T1=10/30=1/3hr.

D2=40km

T2=40/50=0.8hr

Average speed = d1+d2 / t1+t2

10+40 / 1/3+0.8

= 45.4

Answer = 45.4 km/hr

Previous Question

Next Question

Similar questions

English, 2 months ago

definition of puffed out...

Math, 2 months ago

The perimeter of a rectangle is 30m and the ratio between length and breadth is 7:3. Find area?

Math, 2 months ago

A 16\dfrac1216 2 1 16, start fraction, 1, divided by, 2, end fraction kilometer stretch of road needs repairs. Workers can repair 2\dfrac142 4 1 2, start fraction, 1, divided by, 4, end fraction kilometer of road per week. How many weeks will it take to repair this stretch of road? weeks...

Physics, 4 months ago

The average velocity of a body is given by the expression?

Math, 4 months ago

Find the inverse laplace Transform of 6s-4÷ 4s+20...

Science, 11 months ago

2. The ratio of distance on a map to actual distance is known as the------------------- the map...

Math, 11 months ago

The set {{(0,6] ∪ (3,8]} ∩ (1,9)} is equal to (1,8) (1,8] (3,9) (3,8] ...

Social Sciences, 11 months ago

make a list of festival that might have been celebrated by (a) ram (b) rahim...