Question

a body travels a distance of 15 m from a to b and then moves a distance of 20 m at right angles to a bi calculate the total distance travelled and the displacement​

Answer 1

Answer:

Distance is total length of path travelled i,e. is A+B =15+20=35

Displacement → AC^2 =BC^2+CA^2

= 15^2+20^2

= 225 + 400

= 625

So displacement is 25

Explanation:

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Answer 2

Answer:

The distance and displacement covered by the body are 35m and 25m respectively.

Explanation:

Given that,

A body travels a distance of 15 m from A to B and then moves a distance of 20 m at right angles to AB.We are required to calculate the total distance travelled and the displacement.

Distance is the sum of the lengths AB and BC.Therefore,

$distance = AB+BC \\ = 15m + 20m = 35m$

The displacement is length which is hypotenuse to the sides AB and BC.It is found as follows

$displacement=\sqrt{AB^{2}+BC^{2}} \\ = \sqrt{ {15}^{2} + {20}^{2} } = 25m$

Therefore,the distance and displacement covered by the body are 35m and 25m respectively.

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