Physics, asked by XxPUSHPENDRAxX, 6 months ago

A body travels a distance of 2m in 2s. 2.8m in next 4sec.What will be speed of body in 10th second of its journey

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Answered by SugaryCherrie

Answer:

S=ut+1/2at²

2=2u+2a------>(1)

4.8=6u+18a---->(2)

Multiplying (1) by 3,

6u+6a=6

6u+18a=4.8

-------------

-12a=1.2

a=-0.1 m/s²

Therefore,

u=(2-2a)/2= 0.8 m/s

Hence, distance travelled in the 10th second is---> S=u-1/2a(2n-1)

S=0.8-0.1(20-1)= 0.8-1.9= -1.1m( displacement) which is 1.1m in distance

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Answered by ajanya123

Answer:

let initial velocity be u and acceleration be a .

thus, distance travelled in 2sec is 2 m , using 2nd equation of motion :

2=u+1/2a(2)^2

1= u+ a

also distance in next four seconds , i.e between 6th and 2nd seconds is 2.8m .

2.8 = u(6) + 1/2a(6) - u(2)+1/2a(2)^2

0.7 = u+4a

solving the above two equations we get :

u= 1.1 m/s

a= 0.1 m/s ^2

distance travelled in 10 sec , using 2nd equation of motion

s= (1.1) (10)+ 1/2 ( -0.1)(10)^2

s= 6min

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A body travels a distance of 2m in 2s. 2.8m in next 4sec.What will be speed of body in 10th second of its journey​

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A body travels a distance of 2m in 2s. 2.8m in next 4sec.What will be speed of body in 10th second of its journey