a body travels a distance of 3km towards east, then 4km towards north and finally 9km towardseast. what is the distance travelled and displacement?
yashladep5hgs2:
is there in formation about time or speed
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Answered by
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Hello friend
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Here is your answer
Given
A body travels a distance of 3km towards east, then 4km towards north and finally 9km towardseast.
Total distance = (3+4+9 )km
Total distance traveled by a body = 16km
=> Displacement is the shortest path
Let
A= 3 ,b=4 and c= 9
(Displacement )^2= (a+c) ^2+ b^2
=> (3+4)^2+9^2
=>144+16
=>160km
Were
Displacement =√160km
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Hope it's help u
-------------
Here is your answer
Given
A body travels a distance of 3km towards east, then 4km towards north and finally 9km towardseast.
Total distance = (3+4+9 )km
Total distance traveled by a body = 16km
=> Displacement is the shortest path
Let
A= 3 ,b=4 and c= 9
(Displacement )^2= (a+c) ^2+ b^2
=> (3+4)^2+9^2
=>144+16
=>160km
Were
Displacement =√160km
-----------------
Hope it's help u
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