if alpha and beta are the zeroes of the polynomial 3x2+8x+2=0 then find the value of alpha2+beta2
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Answered by
73
Here is your answer :-
Equation is 3x² + 8x + 2
On comparing this equation ,
a = 3 , b = 8 , c = 2
sum of zeroes = -b /a
alpha + beta = -8/3
product of zeroes = c/a
alpha × beta = 2/3
alpha ² + beta² = (alpha + beta ) ² - 2alpha× beta
( -8/3)² - 2 × 2/3
64/9 - 4/3
52/9
hope it helps you ...mark as brainiliest
Equation is 3x² + 8x + 2
On comparing this equation ,
a = 3 , b = 8 , c = 2
sum of zeroes = -b /a
alpha + beta = -8/3
product of zeroes = c/a
alpha × beta = 2/3
alpha ² + beta² = (alpha + beta ) ² - 2alpha× beta
( -8/3)² - 2 × 2/3
64/9 - 4/3
52/9
hope it helps you ...mark as brainiliest
AkashSureshbabu:
thank you ...means a lot
Answered by
3
Here is your answer :-
Equation is 3x² + 8x + 2 On comparing this equation ,
a = 3 , b = 8 , c = 2
sum of zeroes = -b /a
alpha + beta = -8/3
product of zeroes = c/a
alpha × beta = 2/3
alpha ² + beta² = (alpha + beta ) ² - 2alpha× beta
( -8/3)² - 2 × 2/3
64/9 - 4/3
52/9
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