Question

A body travels a distance s1 with velocity v1 and s2 with v2 in the same direction, calculate average velocity.

Answer 1

Time taken by the body to travel s1 distance= S1/V1 seconds

 Time taken by the body to travel s2 distance = S2/V2 seconds

 Total time taken by the body to travel = (s1/v1) + (s2/v2) equals to (s1v2 + s2v1) divides by (v1 + v2)

 Therefore, total displacement = s1 + s2

  Average velocity= (s1 + s2) / [ (s1v2 + s2v1)

divides by (v1 + v2) = (s1 + s2) (v1 + v2)

divided by (s1v2 + s2v1) .

= (s1v1 + s2v2) + (s1v2 +s2v1)

divided by (s1v2 + s2v1) .

= [ (s1v1 + s2v2) / (s1v2 + s2v1) ] + [ (s1v2 +s2v1) / (s1v2 + s2v1) ] .

 = [ (s1v1 + s2v2) / (s1v2 + s2v1) ] + 1

Answer 2

Answer:

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