A body travels along a straight line with speed V¹ for time t¹ and other distance with speed V² for the t² in the same direction. Find the average speed of the body.
Answers
Answered by
4
HERE IS THE SOLUTION;
◆Let, the total distance covered by the particle during the complete journey is 2x.
◆If The half distance (x) covered with the speed v1 in t1 time.
◆Using formula of speed, v1=x/t1
so, t1= x/v1
◆And another half distance (x), covered with speed v2 in time t2.
so, v2=x/t2
t2=x/v2
◆AVERAGE VELOCITY = Total distance /Total time
◆Total time= t1+t2 = x/v1 + x/v2
=(v2x+v1x)/v1v2
◆Total distance = x+x=2x
◆On putting the values of total distance and total time in the formula of average speed, we get
◆Average speed= 2x /(v2x+v1x / v1v2)
= 2v1v2 /(v1+v2)
HOPE IT HELPS
◆Let, the total distance covered by the particle during the complete journey is 2x.
◆If The half distance (x) covered with the speed v1 in t1 time.
◆Using formula of speed, v1=x/t1
so, t1= x/v1
◆And another half distance (x), covered with speed v2 in time t2.
so, v2=x/t2
t2=x/v2
◆AVERAGE VELOCITY = Total distance /Total time
◆Total time= t1+t2 = x/v1 + x/v2
=(v2x+v1x)/v1v2
◆Total distance = x+x=2x
◆On putting the values of total distance and total time in the formula of average speed, we get
◆Average speed= 2x /(v2x+v1x / v1v2)
= 2v1v2 /(v1+v2)
HOPE IT HELPS
Similar questions