two numbers are in ratio of 5:8.if the sum of numbers is 182.find the numbers
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Answered by
6
Given that two numbers are in the ratio 5:8.
Let the first number be 5x. ---- (1)
Let the second number be 8x. ---- (2)
Given that sum of numbers is 182.
5x + 8x = 182
13x = 182
x = 14
Substitute x = 14 in (1)& (2), we get
1st number = 5 * 14 = 70
2nd number = 8 * 14 = 112.
Therefore, the numbers are 70 and 112.
Hope this helps!
Let the first number be 5x. ---- (1)
Let the second number be 8x. ---- (2)
Given that sum of numbers is 182.
5x + 8x = 182
13x = 182
x = 14
Substitute x = 14 in (1)& (2), we get
1st number = 5 * 14 = 70
2nd number = 8 * 14 = 112.
Therefore, the numbers are 70 and 112.
Hope this helps!
AmanChodhary:
thanks
Answered by
3
Hey!
Given,
Ratio=5:8
Sum of these numbers =182
Let the numbers =5x and 8x
ATQ,
182=5x + 8x
182=13x
182/13=x
14=x
Hence,
1st number=5x=5×14
=70
2nd number =8x = 8×14
=112
The numbers are 70 and 112.
Hope this helps.............
Given,
Ratio=5:8
Sum of these numbers =182
Let the numbers =5x and 8x
ATQ,
182=5x + 8x
182=13x
182/13=x
14=x
Hence,
1st number=5x=5×14
=70
2nd number =8x = 8×14
=112
The numbers are 70 and 112.
Hope this helps.............
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