a body travels from a distance of 15 m from A to B and then moves a distance of 20 m at right angles to AB. calculate the total distance travelled and displacement
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total distance =15+20=30m and displacement =25m
senthilkumark:
nice
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Solution:-
given by:-
》distance A TO B = 15 M
》B to C = 20 m
》total distance = 35m
》displacement = AC^2 = AB^2 + BC^2
》 = AC = (15^2+20^2)^1/2
》 = AC = ( 225+400)^1/2
》 = AC = 625^1/2
》 =( AC = 25 m)ans
given by:-
》distance A TO B = 15 M
》B to C = 20 m
》total distance = 35m
》displacement = AC^2 = AB^2 + BC^2
》 = AC = (15^2+20^2)^1/2
》 = AC = ( 225+400)^1/2
》 = AC = 625^1/2
》 =( AC = 25 m)ans
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