Physics, asked by Smritiram, 1 year ago

Hi! Could someone explain this problem clearly? A hammer weighing 2.5kg moving with a velocity of 1m/s strikes the head of the nail driving it 10cm into the wall. What is the acceleration during the impact and the impulse imparted to the wall?

Answers

Answered by abi2790
1
we know the formula,

v2 = u2 + 2as

10 cm = 0.1 m

02 = 12 + 2*a * 0.1

- 1 = 0.2 * a

-1 / 0.2 = a

a = - 5 m / s2

Impulse = Change in momentum

= m(v - u)

= 2.5 kg ( 0 - 1)

= - 2.5 kg m /s

Acceleration : - 5 m /. s2

Impulse = - 2.5 kg m / s

Smritiram: Thank you very much!
abi2790: Your welcome ;)
Similar questions