Hi! Could someone explain this problem clearly? A hammer weighing 2.5kg moving with a velocity of 1m/s strikes the head of the nail driving it 10cm into the wall. What is the acceleration during the impact and the impulse imparted to the wall?
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we know the formula,
v2 = u2 + 2as
10 cm = 0.1 m
02 = 12 + 2*a * 0.1
- 1 = 0.2 * a
-1 / 0.2 = a
a = - 5 m / s2
Impulse = Change in momentum
= m(v - u)
= 2.5 kg ( 0 - 1)
= - 2.5 kg m /s
Acceleration : - 5 m /. s2
Impulse = - 2.5 kg m / s
v2 = u2 + 2as
10 cm = 0.1 m
02 = 12 + 2*a * 0.1
- 1 = 0.2 * a
-1 / 0.2 = a
a = - 5 m / s2
Impulse = Change in momentum
= m(v - u)
= 2.5 kg ( 0 - 1)
= - 2.5 kg m /s
Acceleration : - 5 m /. s2
Impulse = - 2.5 kg m / s
Smritiram:
Thank you very much!
Your welcome ;)
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